## 2015年4月13日星期一

### 12 volt power inverters

12V inverter performance test where test input power supply with low internal resistance, discharge current is large (typically greater than 100A) of the 12V car battery, can provide sufficient input power circuit. Test load
For ordinary light bulbs. The method of testing is by changing the size of the load, and this time was measured input current, voltage and output voltage. The test results are voltage and current curves of relationships. As can be seen, the output voltage decreases with increasing load, 300 watt power inverter consumption of the lamp voltage-dependent changes. We can also find out by calculating the relationship between the output voltage and power. But in fact due to the resistance of the light bulb will vary by plus changes in the voltage across the change, and the output voltage and current is not a sine wave, so this calculation can only be regarded as estimates. With a load of 60W light bulb, for example: assume that the lamp voltage does not vary with changes in the resistance to change. Because R lamp = V2 / W = 2102/60 = 735Ω, 500w power inverter when the voltage is 208V, W = V2 / R = 2082/735 = 58.9W. Thus can be converted into a voltage and power relations. Through testing, we found that when the output power of about 100W, the input current is 10A. Then the output voltage is 200V. Inverter power efficiency characteristics shown in Figure 15b. When the inverter continuous 100W load, FET.